Do I need a linear regulator in this circuit?

[syedj94]

Hi,
I am trying to build a portable usb charger the outputs 5V when input is 1.5 or 3 Volts. I found this step up converter: goo.gl/RAV9dC
The spec for the converter state that the input voltage is 1V to 10V, and the out put Voltage is -1.5V to -10V and 3V to 10V. I frankly don't know how to interpret this information.
It seems to me that by inputting 1.5V, the output will be 10V. So I am wondering if am right, and IF I am, then do I need to put in a 5V voltage regulator in the circuit?
Thanks!

 

[chuckey]

I googled RAV9dC and only got your questions , are you sure this is the correct type number?
Frank

 

[keith1200rs]

I believe the posts refers to the MAX1044 but in a rather cryptic way!

Keith

 

[syedj94]

I googled RAV9dC and only got your questions , are you sure this is the correct type number?
Frank

It is shortened url.
www.goo.gl/RAV9dC

 

[keith1200rs]

Or more concisely, it is the MAX1044!

Keith

 

[BradtheRad]

The IC spec implies it can step up or step down. It suggests it can drive a coil as a buck-boost converter.

Here is a simulation showing how the output can be -5V whether the supply is 1.5V or 3V. The duty cycle is the only thing you need to change.



Notice you can also connect the load across the output and the positive polarity. This provides a higher additional range of positive output V. (I believe the IC specs reflect this.)

You would probably construct a boost converter (rather than a buck-boost).