Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Register Log in

Differential Output Current

Status
Not open for further replies.
E

ebernz

Newbie level 1
Joined
May 28, 2009
Messages
1
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Activity points
1,286
Hi guys, Need help on identifying or maybe confirming my equation on determining the differential output current (double ended) on this circuit.

Differential_circuit.jpg


Am I corrent?

Idiff(double ended) = 1/2(Ip-In)
 

As long as your circuit doesn't show a load and Idiff, it can't be answered unequivocally.
Also, if Ip and In are meant to be the transistor output currents, they should be drawn as such.
Furthermore, it's confusing to draw opposite polarity for Ip and In. In this case, Ip-In can't be correct.
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top