Dc power calucation of varying load

[chethankp]

Hi,
I need to calulate the power drawn by the load for one hours
my current readings are like this

1-10 sec -->10mamp
10-200 sec -->100mamp
200-2000 sec -- > 5mamp
2000-6000 -- > 15 mamp

Since its a DC power I sed this formula

P = v*i
in my case c = 3v
hence
p = 3 *( (10*10/6000) + ((190*100)/6000) + ((1980*5)/6000) + (4000 *15)/6000)) ;

is the above calculation is correct for my reading ?

I felt I am doing wrong calculation

 

[albbg]

The general formula you used is correct to calculate the average power over the period is correct. But It seems to me there is something strange:

why the time doesn't start from 0 but from 1 s ? (if, due to some reason, this is correct the first interval is 9 s instead of 10 s as you used)
in an hour there aren't 6000 seconds but only 3600.

 

[Gimlix]

This is just drawing an average of 14.63mAh. If the voltage is constant, it would be 43.89mW.