Jun 25, 2015 #1 C curiouscase Junior Member level 1 Joined Jan 16, 2015 Messages 15 Helped 4 Reputation 8 Reaction score 4 Trophy points 3 Activity points 83 Can anyone tell me the cut-off wavelength of dielectric filled waveguide? Last edited by a moderator: Jun 25, 2015
Jun 25, 2015 #2 FvM Super Moderator Staff member Joined Jan 22, 2008 Messages 52,414 Helped 14,749 Reputation 29,780 Reaction score 14,097 Trophy points 1,393 Location Bochum, Germany Activity points 298,073 I guess cut-off frequency of regular wave guide, divided by square root (Er).
Jun 25, 2015 #3 J jiripolivka Advanced Member level 5 Joined May 21, 2010 Messages 2,831 Helped 832 Reputation 1,662 Reaction score 803 Trophy points 1,393 Location Santa Barbara Activity points 22,010 FvM said: I guess cut-off frequency of regular wave guide, divided by square root (Er). Click to expand... Also depends on a particular mode.
FvM said: I guess cut-off frequency of regular wave guide, divided by square root (Er). Click to expand... Also depends on a particular mode.
Jun 25, 2015 #4 FvM Super Moderator Staff member Joined Jan 22, 2008 Messages 52,414 Helped 14,749 Reputation 29,780 Reaction score 14,097 Trophy points 1,393 Location Bochum, Germany Activity points 298,073 Also depends on a particular mode. Click to expand... O.K., it's not only multiplying the wavelength with √Er, you also have to put in the reduction factor for width and height when calculating the cut-off frequency. But in case of a completely filled waveguide, it's just a geometry factor.
Also depends on a particular mode. Click to expand... O.K., it's not only multiplying the wavelength with √Er, you also have to put in the reduction factor for width and height when calculating the cut-off frequency. But in case of a completely filled waveguide, it's just a geometry factor.