current rate problem

[rakirajueee08]

I am trying to convert a ac signal of voltage 7v and about 1A current.when i convert it to dc by full bridge rectifier of general diode 1N4007 .The problem is after converting it into dc voltage is about 5-6v but the current is so low about 10ma.what is the problem.please help me someone.

 

[pinout]

Is this a real circuit or simulation?
When you say 'signal' I presume you mean source or power and its a 7V 1A rated transformer?
Is there any capacitive load across the bridge rectifier output?
What is the actual load and how are you measuring the volts and current?

 

[betwixt]

As this is in the RF section of the forum, what frequency is the signal? 1N4007 diodes are only good to a few KHz, anything higher will need a device with faster recovery characteristics.

Brian.

 

[rakirajueee08]

I am doing a project on wireless power transfer.In that I am giving a signal of frequency 2Mhz and in my secondary a voltage is being induced at frequency 2MHZ.And the induced voltage in ac is about 7-8 v and current is 1 A.After rectification with this diode 1N4007 full bridge current is decreasing to 10ma.But I need minimum 500ma.

 

[jiripolivka]

I am doing a project on wireless power transfer.In that I am giving a signal of frequency 2Mhz and in my secondary a voltage is being induced at frequency 2MHZ.And the induced voltage in ac is about 7-8 v and current is 1 A.After rectification with this diode 1N4007 full bridge current is decreasing to 10ma.But I need minimum 500ma.

What is your "signal" source and how did you measure the voltage and current? At 2 MHz, common DVMs do not function and cannot read voltage or current. 1N4007 does not operate at 2 MHz either. Find a fast-recovery Schottky rectifier and use a 10 uF in parallel with 0.1 uF across output terminals.