5V across pins 2/3 means the current limiting transistor is broken. Or the measurement incorrect. You should be able to detect a diode junction between pins 2 and 3 at the unconnected IC.
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One problem of the circuit is that it misses any base-emitter pull-down resistor. Shut down in current limit is very slow.
The circuit is apparently incomplete, no reference path, no frequency compensation. If you manage to get the circuit oscillating, it may quickly blow the current limit transistor. You may want to place a series current limiting resistor for pin 2, e.g. 100 ohm.