Jan 2, 2007 #1 V verda Newbie level 1 Joined Jan 2, 2007 Messages 1 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,284 2(dy/dx)=ytanx
Jan 2, 2007 #2 G gepla Newbie level 5 Joined Mar 25, 2005 Messages 9 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,332 2(dy/dx)=y.tanx ∫2dy/y = ∫tanx.dx 2ln|y| = - ln|cosx| + C ln(y²) = -ln|cosx| +lnc1 ln(y²) = ln(c1/|cosx|) y² = c1/|cosx| y = ±√(c1/|cosx|) with cosx≠0 and c1>0
2(dy/dx)=y.tanx ∫2dy/y = ∫tanx.dx 2ln|y| = - ln|cosx| + C ln(y²) = -ln|cosx| +lnc1 ln(y²) = ln(c1/|cosx|) y² = c1/|cosx| y = ±√(c1/|cosx|) with cosx≠0 and c1>0