convolution of two gaussians
Hi purna,
The result is a gaussian pulse sqrt(2) times wider.
You get this result by directly solving the convolution integral.
Another interesting way to consider this is as follows:
The Fourier transform (FT) of a gaussian pulse (in time) is a gaussian function (in frequency). This if found by solving the integral of the FT.
The product of the gaussian function by itself is a gaussian function, sqrt(2) times narrower. This is easy to show.
Going back to time domain, and using FT properties, you conclude that the convolution of a gaussian pulse by itself is a gaussian pulse sqrt(2) times wider.
Regards
Z