Sep 11, 2008 #1 C Chest Member level 3 Joined Sep 18, 2006 Messages 67 Helped 2 Reputation 4 Reaction score 1 Trophy points 1,288 Activity points 1,756 lin mag Hi all, Anyone know how to convert from 'LIN MAG' to 'LOG MAG'? Thanks in advance.
Sep 11, 2008 #2 F fanshuo Full Member level 5 Joined Jun 21, 2007 Messages 266 Helped 8 Reputation 16 Reaction score 4 Trophy points 1,298 Location Netherlands Activity points 2,746 convert linmag to logmag use the exponential property of bipolar devices
Sep 11, 2008 #3 B biff44 Advanced Member level 6 Joined Dec 24, 2004 Messages 5,047 Helped 1,376 Reputation 2,748 Reaction score 1,056 Trophy points 1,393 Location New England, USA Activity points 37,910 +20 log 10 Depends. If you are measuring voltages or phase noises, use 'Log mag' = 20 Log ('Lin Mag'). If you are measuring power, 'Log Mag' = 10 Log ('Lin Mag') Ex: 0.1 mW is the same as 10 Log (0.1 mw/1 mw) = -10 dBm or 0.2 volts is the same as 20 Log (0.2v/1 v) = -13.9 dbv
+20 log 10 Depends. If you are measuring voltages or phase noises, use 'Log mag' = 20 Log ('Lin Mag'). If you are measuring power, 'Log Mag' = 10 Log ('Lin Mag') Ex: 0.1 mW is the same as 10 Log (0.1 mw/1 mw) = -10 dBm or 0.2 volts is the same as 20 Log (0.2v/1 v) = -13.9 dbv
Nov 14, 2008 #4 kspalla Advanced Member level 4 Joined Aug 19, 2008 Messages 1,253 Helped 258 Reputation 516 Reaction score 94 Trophy points 1,328 Location Hyderabad, Andhra Pradesh, India Activity points 6,813 convert lin mag to logmag Have you tried dB() function?
Nov 14, 2008 #5 Y yours Newbie level 6 Joined Apr 19, 2007 Messages 11 Helped 1 Reputation 2 Reaction score 0 Trophy points 1,281 Activity points 1,333 convert linear mag to log mag biff44 said: Depends. If you are measuring voltages or phase noises, use 'Log mag' = 20 Log ('Lin Mag'). If you are measuring power, 'Log Mag' = 10 Log ('Lin Mag') Ex: 0.1 mW is the same as 10 Log (0.1 mw/1 mw) = -10 dBm or 0.2 volts is the same as 20 Log (0.2v/1 v) = -13.9 dbv Click to expand... I think there is something wrong. Measuring power is 20log(). Measuring voltages is 10log().
convert linear mag to log mag biff44 said: Depends. If you are measuring voltages or phase noises, use 'Log mag' = 20 Log ('Lin Mag'). If you are measuring power, 'Log Mag' = 10 Log ('Lin Mag') Ex: 0.1 mW is the same as 10 Log (0.1 mw/1 mw) = -10 dBm or 0.2 volts is the same as 20 Log (0.2v/1 v) = -13.9 dbv Click to expand... I think there is something wrong. Measuring power is 20log(). Measuring voltages is 10log().
Nov 14, 2008 #6 radiohead Advanced Member level 1 Joined May 13, 2004 Messages 447 Helped 66 Reputation 128 Reaction score 31 Trophy points 1,308 Location Heart of Europe Activity points 3,562 phase to logmag yours said: biff44 said: Depends. If you are measuring voltages or phase noises, use 'Log mag' = 20 Log ('Lin Mag'). If you are measuring power, 'Log Mag' = 10 Log ('Lin Mag') Ex: 0.1 mW is the same as 10 Log (0.1 mw/1 mw) = -10 dBm or 0.2 volts is the same as 20 Log (0.2v/1 v) = -13.9 dbv Click to expand... I think there is something wrong. Measuring power is 20log(). Measuring voltages is 10log(). Click to expand... Nah. Power is 10log, voltage is 20log.
phase to logmag yours said: biff44 said: Depends. If you are measuring voltages or phase noises, use 'Log mag' = 20 Log ('Lin Mag'). If you are measuring power, 'Log Mag' = 10 Log ('Lin Mag') Ex: 0.1 mW is the same as 10 Log (0.1 mw/1 mw) = -10 dBm or 0.2 volts is the same as 20 Log (0.2v/1 v) = -13.9 dbv Click to expand... I think there is something wrong. Measuring power is 20log(). Measuring voltages is 10log(). Click to expand... Nah. Power is 10log, voltage is 20log.
Nov 15, 2008 #7 A Azulykit Advanced Member level 4 Joined Feb 18, 2007 Messages 1,140 Helped 224 Reputation 446 Reaction score 116 Trophy points 1,343 Location All over the Map. Activity points 8,630 lin mag to log mag Just think of voltage squared is proportional to power. That is why the 20 or 10 log is applied depending on the argument of the log function (voltage or power units).
lin mag to log mag Just think of voltage squared is proportional to power. That is why the 20 or 10 log is applied depending on the argument of the log function (voltage or power units).