Clarification regarding calculating input power of Power Amplifier

P

pusparaga

Full Member level 4
Joined
Oct 19, 2013
Messages
197
Helped
4
Reputation
8
Reaction score
4
Trophy points
1,298
Activity points
2,988
I want to find out input power for desired output power of a Power Amplifier. Below, I have attached formula for finding out input power. I have got confused with this formula. In the formula they are saying input power = (output power required - gain as mentioned in the data sheet) + 3 dB. I want to find out 38 Watts output power at 3.50 GHz. Gain is around 15 dB at 3.50 GHz. What should be the input power. I get confused how to find out input power using this formula. Clarify this issue.
 

Attachments

  • OutPut_Power_Calculation.jpg
    33.9 KB · Views: 42
  • Gain_Efficiency_Psat_Graph.jpg
    117.3 KB · Views: 45

Sort by date Sort by votes
volker@muehlhaus said:
15 dB - 3dB = 12dB
12dB power gain is factor 10^(12/10) = 15.8
38W / 15.8 = 2.4 W
Click to expand...
Pin(dBm) = 38 Watts- 15 dB + 3 dB
Pin(dBm) +15 dB - 3 dB = 38 Watts
Pin(dBm) + 12 dB = 38 Watts
My doubt is how it becomes 38W/ 15.8. dB cannot be converted to dBm. It can be converted dBm
into Watts easily.
Don't mind. Clarify it
 

Upvote 0 Downvote
You must log in or register to reply here.

Similar threads

Menu
Log in
Register
Cookies are required to use this site. You must accept them to continue using the site. Learn more…