Dec 4, 2010 #1 M marcofh Newbie level 3 Joined Dec 4, 2010 Messages 3 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,293 pleaase help me to understand how to solve the circuit attached finding i. thanks Attachments circuit.jpg 16.8 KB · Views: 113
Dec 4, 2010 #2 S seadolphine2000 Advanced Member level 3 Joined Apr 12, 2005 Messages 880 Helped 122 Reputation 244 Reaction score 87 Trophy points 1,308 Activity points 7,372 Here you are the steps: R1 = 2KOhm, R2 = 4KOhm, R3 = 10KOhm and, R4 = 5KOhm 1- R1//R2 = 4/3 KOhm 2- R3//R4 = 10/3 KOhm 3- Voltage across R1//R2 = V12 = 3mA * (R1//R2) = 4V 4- Voltage across R3//R4 = V34 = 3mA * (R3//R4) = 10V 5- i = (V12/R1) - (V34/R3) = (4/2KOhm) - (10/10KOhm) = 1 mA
Here you are the steps: R1 = 2KOhm, R2 = 4KOhm, R3 = 10KOhm and, R4 = 5KOhm 1- R1//R2 = 4/3 KOhm 2- R3//R4 = 10/3 KOhm 3- Voltage across R1//R2 = V12 = 3mA * (R1//R2) = 4V 4- Voltage across R3//R4 = V34 = 3mA * (R3//R4) = 10V 5- i = (V12/R1) - (V34/R3) = (4/2KOhm) - (10/10KOhm) = 1 mA
Dec 4, 2010 #3 M marcofh Newbie level 3 Joined Dec 4, 2010 Messages 3 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,293 thanks!! great!