rajaram04
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Scariest circuit I have not seen recently.
AC voltage is rectified by the full wave rectifier formed of D1 through D4.The rectified voltage is reduced to a safer level by the resistor R1.The low volt DC is then made ripple free by C1 and regulated to 5 volt DC by the Zener diode ZD. Transistor T1 and T2 form an oscillator with capacitor C3 and resistor R2. The charging and discharging of C3 through R2 makes T1 and T2 oscillating.LED connected to the positive of C5 flashes depending on the charge and discharge of C5.When C3 fully charges, T1 conducts and its collector pulls the base of T2 to ground and it also conducts. This causes the discharge of C5. When C3 discharges, T1 and T2 turns off and now C5 charges through R4.This causes the Flashing of LED.
Caution: Shock Hazard! This circuit is directly connected to High volt AC. Do not construct the circuit if you are not experienced in handling AC voltage. Do not touch any points when connected to mains.
https://www.electroschematics.com/5604/led-flasher/
No, you should not.i shud not go for it ?
so sir as per you its not good at all ? i shud not go for it ?
This circuit is perfectly alright to work with. Instead of using a 1W 22K res which will heat up in due time, on the ac side use a step down transformer.
I hope, unused charger of mobile decide problem electrical hazard and R1 burn out. The more so that the power dissipated in R1 is 0.01A*220V=2W not 1W, as indicated in the diagram, which is a direct diversion.
Why don't you go for a easier and safer LED flasher circuit...just google it and you'll find lots of them.