thanks.. i came across this boost converter circuit that uses some other mosfet and drivers. i need it modified to suit my application.. i have very little time to finish the project so i need some help here.. i m currently doin the programming for the PIC control of my boost converter.
Which driver did you choose? Did you go through the datasheet? Are you done with the coding?
You can take the MOSFET, inductor, capacitor etc - ie the power boost stage - from this circuit as it is pretty much the same for all boost converters. You'll need to change the driver stage, using your driver. Also, change the feedback section - here a simple resistive divider is used, so you might need to change it depending on the code; the values are blurred in the picture, so can't read the value.
ya it helped a lot.. can you just tell me what i need to add if i am going to use current sensing.. i know it involves op amps but i m not sure..and also suggest a value for the inductance.. i will make the changes you asked and attach the diagram soon.. thanks a lot
Use R5 for current sensing. Measure the voltage across R5 using the PIC ADC and determine what is to be done at which current setting in the code. V=IR, so I=V/R. Use this information in the PIC code to determine the current by measuring the voltage.
Ensure that you connect a small RC filter. You can use a 1kΩ resistor and a 0.01µF or 0.1µF capacitor.
Yes. The values are not so critical and if any problem arises, you can tweak the values through trial and error. 1kΩ resistor and a 0.01µF or 0.1µF capacitor is a good starting point.
Hello People
I have a similar doubt in same domain
my question is : since we know how to control output voltage of boost converter, but what are the factors which dictates output power, i.e. output current. Is it only the capacitor which determines it?
and in case of a mosfet switch, mosfet should be choosen to match the corresponding current?
If output current is 0.3A at 24V output voltage, the output power is 24*0.3=7.2W
Peak current = (5.5 * Power output)/(Minimum input voltage)
So, you should choose a MOSFET with a current rating higher than the peak current (you should keep a significant margin), with a low enough RDS(on) to minimize losses.
Conduction loss in the MOSFET = (I^2)*R. R here would be RDS(on), I would be current flowing through the MOSFET.
Hey Tahimd,
Can I ask how do the 5.5 get from in your formula Peak current = (5.5 * Power output)/(Minimum input voltage), I really appreciate if you can quota a detailed formula or a something else. I'm confused with this stuff for a long time.
Thanks!
..... the strange part is my input is a solar panel which is supposed to be a 12V 20W panel but its giving me an output of 24 v in the sun.. can anyone explain why?? ................
The reason the rated voltage is about 1/2 the maximum voltage is that, from the Maximum Power Transfer Theorem, the maximum output power from the solar panel occurs when the load resistance is equal the panel internal resistance. This will give an output voltage of 1/2 the open circuit voltage of the panel. Thus MPPT power supplies maximize output power by automatically adjusting the load so that is always equals the panel impedance.
Hello ,
I am trying to build a sepic converter for Mppt charge controller and I have simulated the same in NL5 simulation and Proteus ..They seem to be working fine..I am using IRF540 ...Which gate driver to use ?ucc2701,Ir2110,Ir2184 or Uln2803...??