preethi19
Full Member level 5
Hi i have attached the figure of an inverting op-amp.
op-amp one of the aspect is
"The output does what it takes to make sure the two input voltages are the same".
I can understand how the output voltage Vout expression is brought about. Its quite simple and straightforward. I found this example online
Let's take an example; let R1 = 10k, R2 = 100k, Vin = 0.2v.
A = -100k / 10k = 10 * 0.2v so the output voltage is -2v.
I understand this calculation. We have determined the output voltage to be -2V. But from here on can anyone explain me with simple equation how the feed back works such that the 0.2V input voltage becomes 0 (since one of the input is grounded) and since op-amp tries to match both the inputs how is 0.2V reduced to 0V. I can understand only till finding the output voltage but not how this -2V is fed back such that the input is reduced to 0 matching the gnd. Can anyone kindly explain this part. Thank you!!!
op-amp one of the aspect is
"The output does what it takes to make sure the two input voltages are the same".
I can understand how the output voltage Vout expression is brought about. Its quite simple and straightforward. I found this example online
Let's take an example; let R1 = 10k, R2 = 100k, Vin = 0.2v.
A = -100k / 10k = 10 * 0.2v so the output voltage is -2v.
I understand this calculation. We have determined the output voltage to be -2V. But from here on can anyone explain me with simple equation how the feed back works such that the 0.2V input voltage becomes 0 (since one of the input is grounded) and since op-amp tries to match both the inputs how is 0.2V reduced to 0V. I can understand only till finding the output voltage but not how this -2V is fed back such that the input is reduced to 0 matching the gnd. Can anyone kindly explain this part. Thank you!!!