1.8W according to my math.I think linear regulators are not very suitable for 60V, 30mA, because this means max 18W of power dissipation.
True, for sure.1.8W according to my math.
Operating a linear current source over a dynamic range of 1:10 (30 - 300 mA) is no problem at all. You didn't yet specify accuracy requirements however.
I read the block diagram so, that you plan to switch the power supply between different voltage and current ranges so that the output transistor power dissipation can be minimized.
1.8W according to my math.
But this circuit is depended on Rset resistance and it will not act a "true constant current source". Because when you call it as "Constant Current Source" it should provide a constant current independent from load resistance.Hi,
i want to make a circuit which can provide a 60V @30mA OF current
as well 5v@300 ma in the same output
But for 30mA, Voltage drop would be very low
and for that i will have to again amplify the same and apply to the Amplifier to amplifiy then it would drive the BJT.
IT WOULD BE VE VERY LONG METHOD.
i want to make it with a cost effective as well low circuitry.
I am attaching my architecture with this.
View attachment 140022
The circuit isn't bad.But this circuit is depended on Rset resistance and it will not act a "true constant current source". Because when you call it as "Constant Current Source" it should provide a constant current independent from load resistance.
Maybe you should give some additional information HOW to do it.Hi
I think you can build a raw current source with a BJT and some resistor, if you know the load resistance.
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