Eshal
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Then calculated L from iL pk & iL min & Capacitor value from On time of switch,load current,discharge of 3%.
@rahdirs
What I understand, is, if on off time of switch is faster then ripples will be low (both current and voltage ripples). If on off time of switch is slower then ripples will be high (both current and voltage ripples). Further, the higher the switching time, the lower the efficiency.And the lower the switching time the higher the efficiency. Am I right ?
The component values i derived were for delivering a maximum of 500 mA,but what is the rated max.current of your battery that is given in its spec.sheet.Is it 500mA ??More, actually I need to use "Type A female USB connector" at the output of the Boost converter through which I could charge my cell phone battery. It has capacity of 1400mAh. So that's why I want output current of 500mA at least.
@rahdirs
Secondly, sir I didn't get how did you calculate L and C values. They are still unclear to me. Where does 1.16us come? Where is, (i/p current.3.2*I = 5*0.5,I=0.87), 3.2 here?
@tpetar
Yes, sure. I will talk about filter in detail too. But not now.
By the way, filter can reduce voltage. it is the good point. it can increase efficiency even at higher switching frequency. I guess!!!
Eshal wrote:
@BradtheRad
Sorry sir, your applet is not running. I think something is missing in my pc in order to run it properly.
@tpetar
No no, I mean just alkaline batteries of 1.5V. 2 alkaline batteries.
Do you want to say about efficiency then?
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