Boolean Algebra help

[mr2turbo]

Hi all,

i have recently looked at some simple logic and come up with Q = (A + 'B) . (B + C) . C

It needs simplifying but i am useless at Boolean and i feel i haven't been taught well at all.

Here's what i did:

Q = (A + 'B) . (B + C) . C

Q = A + B . A + C . 'B + B . 'B + C . C

Q = A + B . A + C . B . 'B + C

Q = A + B . A + C . 'B + C

Firstly i don't even know if what i have done is correct. I have just used the laws and rules where i think they apply. Secondly, i know it will simplify even further.

Please can somebody help!

Thanks

 

[andre_luis]

I think the simplest form possible is as follows:

Q = (A + 'B) . (B + C) . C
Q = (A + 'B) . (B.C + C)
Q = A.B.C + A.C + B.'B.C + 'B.C
Q = A.B.C + A.C + 0 + 'B.C
Q = A.B.C + A.C + 'B.C
Q = C.(A.B + A + 'B)
Q = C.(A.(B + 1) + 'B)
Q = C.(A + 'B)