My mean is , why we should involve ourselves with some definitions ?
For example , when we have two voltage divider resistors as base bias resistors . be can easily consider , VB is given by a simple divide between two resistors ! but the fact is we can't do it because of base current ! but because base current is negligible , we can do it !!
Just one comment:
The classical procedure for designing the voltage divider for base biasing is to select a current through the upper resistor that is (n+1)-times larger than the anticipated base current - with the result that a current n*Ib flows through the lower base resistor. And this approach gives us formulas for both resistors.
Thus, of course it is possible (and it is normally done) NOT to neglect the base current during this design step.
However, this does not mean the base current would assume any control functions.
Recall :
Think about it , carefully , please :
Why collector current has change when we are increasing VBE ? if we look into the semiconductor crystals of an NPN transistor , we'll see the BE voltage will has effect on conduction of a transistor .
but why collector current has changes ? because base current has changes !
i hope you get what i mean and what i'm trying to refer .
My mean is , why we should involve ourselves with some definitions ?
For example , when we have two voltage divider resistors as base bias resistors . be can easily consider , VB is given by a simple divide between two resistors ! but the fact is we can't do it because of base current ! but because base current is negligible , we can do it !!
What i mean is , up to know i didn't pay any attention to this issue , because it didn't have any benefit in design process . but i agree each peoples , should know the fact of this issue ! hence i'm not disgree with knowing this effect . but i'm completely disagree with thinking about this , in design process !
What thread ? your threads ? why you don't search into your created threads ? of course all of us that are here , should tell each other ( ourselves ) about our problems or wrong ways ! thus we can increase our abilities .
Hence an advise :
Just using a paper and a pen and just theorem can't help ! and it won't have any benefit for you . try to design something ! then you'll learn while you're designing something ! it is a big lesson that many years ago , i've learned it . ( i believe when a project is involved with some complexity ! a thing has problem ! it is why i design all of my projects as simple as possible ! and i'm sure that practical issues and experiments are big professors )
I hope you get what i mean .
goldsmith,
No that is plain wrong. Collector current does not depend on base current. I carefully explained that in my last message to Jeffrey Samuel.
Ratch
how do you plan to get your output Characteristics of your CE amplifier
In definition sake I am sure about this equation
Ic= F(Ib,Vce)
That helps us to draw the output characteristic Graph.
Next up is this the input impedance of a CE amplifier is in the order of kohms I agree to it. Whereas the Input impedance of a FET amplifier is well above Mohms This makes the Ig current have no part or role in the function of the FET
But in the case of the BJT the Ib current plays a very significant role making it to be called "The Current Controlled Device"
Period...
Hey Bro how do you plan to get your output Characteristics of your CE amplifier
In definition sake I am sure about this equation
Ic= F(Ib,Vce)
That helps us to draw the output characteristic Graph.
............
But in the case of the BJT the Ib current plays a very significant role making it to be called "The Current Controlled Device"
When input resistance of a CE amplifier isn't important for me , i will select IR1 = 6ib and IR2 = 5ib . and then i'll continue the design process . but when i have an amplifier with the known values of R1 and R2 and when i've to find quiescent point , i can neglect value of ib and then use this formula to find Vb and then VRE and then IC and then ...... For Vb ( base voltage we can neglect ib and then telling :
VCC*R2/R2+R1
Hi RatchAre you asking and answering your question?
Listen carefully ! I don't need to waste my time with some definitions ! because i know the correct term of this issue and i'm using my methods to design a circuit , if i want to teach someone the principles of operation of a transistor i'll tell that someone , about the fact of issue and then i'll tell that someone to don't pay attention to that fact in design process ! it is what i'm doing !I understand what you mean, and know that you are wrong. It won't do any good to repeat the same thing again. You need to look at my message to Jeffrey Samual, and discuss the points I made in my reasoning.
Yes i can remember it exactly and i can remember the answer of the other expert members of this forum to you ! and i can remember many of famous textbooks that are references in famous universities of this world ! and i can remember that i didn't use that funny theorem until know and i didn't have any problem with my transformers without that negative impedance theorem until now .I am referring to the threads where you "remembered" a concept of negative impedance in a transformer, and an input impedance calculation in a CE amplifier. Don't you remember asking about that?
Hi Goldsmith,
at first, I see a contradiction in your sentence "When input resistance of a CE amplifier isn't important for me , i will select IR1 = 6ib and IR2 = 5ib".
Why do you consider the current Ib into this input resistance if it isn`t important for you?
Moreover, I am afraid there is a big misunderstanding on your side. The question is NOT if Ib can be neglected or not during the design of a transistor stage. That is a complete different problem
Of course, Ib is present and should not be neglected for calculating resistor values. But we speak about the question if Ib controls Ic (from the physical point of view).
And this has nothing to do with the existence of Ib. OK?
Let me tell my meaning , accurately .at first, I see a contradiction in your sentence "When input resistance of a CE amplifier isn't important for me , i will select IR1 = 6ib and IR2 = 5ib".
Why do you consider the current Ib into this input resistance if it isn`t important for you?
.........
but when we want have input impedance of 2 k ohms , we can't use the rule of thumb of 6ib and 5ib because we're looking for an special input resistanceSorry, but this claim is simply false. It is no "rule of thumb". Instead, it is correct by 100%.
When a current I1=k*Ib flows through R1, which then is split into two currents one of which is Ib, then the current through R2 is I2=(k-1)*Ib. That´s for sure.
I like to add that - with respect to the original question in post#1 - I don`t appreciate the discussion "real world vs. theory" because we deviate from the original problem.
If somebody neglects Ib during the design process - this is a complete different story.
More than that, sometimes it can be neglected (for example if we set: Ic=Ie) and sometimes it shouldn`t (for my opinion for calculation of the resistive divider) - and sometimes it cannot at all (biasing with one resistor only).
Because I like the sentence from FvM in post#17 I repeat it here again. I think it can serve as an appropriate summary and outcome of the previous discussion:
In other words, don't mix up basic models of transistor operation and calculation methods used in practical design.
To me, this means the following:
A good engineer has to know what`s really going on and what the operating principles of the various active parts are.
Only then he is able to decide if and when he is allowed to simplify things and to use formulas, which are handsome and exact enough for his particular application - even if they do not reflect the physical truth resp. the physical causality.
Besides the BJT I have two other examples:
* Don`t we sometimes treat the NIC (active current source) as a passive part with the value "-R" ?
* Don`t we treat the MILLER effect as an "artificial" reduction of a resistance - although the input current increase it is caused by a second source within the active circuit ?
(Thus, of course anybody uses the equation Ic=beta*Ib but this does not necessarily mean that he does not know about the physical truth).
LvW
.........
but when we want have input impedance of 2 k ohms , we can't use the rule of thumb of 6ib and 5ib because we're looking for an special input resistanceSorry, but this claim is simply false. It is no "rule of thumb". Instead, it is correct by 100%.
When a current I1=k*Ib flows through R1, which then is split into two currents one of which is Ib, then the current through R2 is I2=(k-1)*Ib. That´s for sure.
I like to add that - with respect to the original question in post#1 - I don`t appreciate the discussion "real world vs. theory" because we deviate from the original problem.
If somebody neglects Ib during the design process - this is a complete different story.
More than that, sometimes it can be neglected (for example if we set: Ic=Ie) and sometimes it shouldn`t (for my opinion for calculation of the resistive divider) - and sometimes it cannot at all (biasing with one resistor only).
Because I like the sentence from FvM in post#17 I repeat it here again. I think it can serve as an appropriate summary and outcome of the previous discussion:
In other words, don't mix up basic models of transistor operation and calculation methods used in practical design.
To me, this means the following:
A good engineer has to know what`s really going on and what the operating principles of the various active parts are.
Only then he is able to decide if and when he is allowed to simplify things and to use formulas, which are handsome and exact enough for his particular application - even if they do not reflect the physical truth resp. the physical causality.
Besides the BJT I have two other examples:
* Don`t we sometimes treat the NIC (active current source) as a passive part with the value "-R" ?
* Don`t we treat the MILLER effect as an "artificial" reduction of a resistance - although the input current increase it is caused by a second source within the active circuit ?
(Thus, of course anybody uses the equation Ic=beta*Ib but this does not necessarily mean that he does not know about the physical truth).
LvW
Hi dear LvW
I'm really sorry . yes you're absolutely right and now i'm completely contented with your statement . and i can't tell any thing about it because you are quite right . and i should accept the right issues .
Thank you very much because of your patience and your clarification
Sincerely Yours
Goldsmith
Hi RatchYou seem to have a hard time staying on topic. The topic is whether BJT is voltage or current controlled. Your answers are usually rambling random musings that have hardly any relationship to the reasons and arguments others give to your often mistaken and absurd statements. The participants of this thread are looking for good factual reasoning that either support your assertions, or disprove their arguments. Instead, they receive philosophical dissertations of often inconsequential, nonapplicable, nonessential, irrelevant, and off topic subjects that are unrelated to the subject being discussed.
So, you should try to stay focused on the thread subject, answer others arguments when they present them, and don't stray into areas that don't pertain to the subject being discussed. If you want to discuss another subject, then you should start another thread.
Ratch
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