dineshdeshmuk
Full Member level 5
Are these calculations right ?
Rated apparent power A = 1565*660 = 1.033 kVA
rated power factor p.f. nom. = P/A = 900/1.033 = 0.87
φ = arccos 0,87 = 0,513 rad
tanφ = 0.563
rated reactive power Q = P tanφ = 900*0,563 = 507 kVAR
Let's assume minimum p.f. being 0.7!!!!....then tan φ1 = 1
Without any power factor correction (improvement) the relevant power P1 will be :
P1 = A*0.7 = 723 kw
and the relevant Q1 :
Q1 = P1*tan φ1 = 725 kVAR....
If you want to get improved power factor 1.00, then u need a capacitor bank Q1 worth 725 kVA @ 380 V, then :
725*10^3 = 380^2/Xc
phase impedance Xc = 380^2/725*10^3 = 0.20 ohm
C = 10*6/(ω*Xc) = 10^6/62.8 = 15.9*10^3 μF
Rated apparent power A = 1565*660 = 1.033 kVA
rated power factor p.f. nom. = P/A = 900/1.033 = 0.87
φ = arccos 0,87 = 0,513 rad
tanφ = 0.563
rated reactive power Q = P tanφ = 900*0,563 = 507 kVAR
Let's assume minimum p.f. being 0.7!!!!....then tan φ1 = 1
Without any power factor correction (improvement) the relevant power P1 will be :
P1 = A*0.7 = 723 kw
and the relevant Q1 :
Q1 = P1*tan φ1 = 725 kVAR....
If you want to get improved power factor 1.00, then u need a capacitor bank Q1 worth 725 kVA @ 380 V, then :
725*10^3 = 380^2/Xc
phase impedance Xc = 380^2/725*10^3 = 0.20 ohm
C = 10*6/(ω*Xc) = 10^6/62.8 = 15.9*10^3 μF