Are these calculations right ?

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dineshdeshmuk

Full Member level 5 Are these calculations right ?

Rated apparent power A = 1565*660 = 1.033 kVA

rated power factor p.f. nom. = P/A = 900/1.033 = 0.87

φ = arccos 0,87 = 0,513 rad

tanφ = 0.563

rated reactive power Q = P tanφ = 900*0,563 = 507 kVAR

Let's assume minimum p.f. being 0.7!!!!....then tan φ1 = 1

Without any power factor correction (improvement) the relevant power P1 will be :

P1 = A*0.7 = 723 kw

and the relevant Q1 :

Q1 = P1*tan φ1 = 725 kVAR....

If you want to get improved power factor 1.00, then u need a capacitor bank Q1 worth 725 kVA @ 380 V, then :

725*10^3 = 380^2/Xc

phase impedance Xc = 380^2/725*10^3 = 0.20 ohm

C = 10*6/(ω*Xc) = 10^6/62.8 = 15.9*10^3 μF

kak111 Supply voltage is ...

---If from load data what are all those marked values.

---If measured what was the measuring circuit and values.

After first quick look something is wrong in this

phase impedance Xc = 0.2 ?????

dineshdeshmuk

Full Member level 5 I read this somewhere , these are not my calculations , I simply copy pasted it , but i don't know , about them right or wrong ?

danishdeshmuk how to calculate or measure the XL value for the generator ? How to do that ?

danishdeshmuk can we calculate the inductance of a coil by knowing the resistance ?

i.e. if the resistances of the three coils are known then can we calculate the inductances of all the three coils ?

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