jasmin_123
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Unless there is series inductance, which wasn't mentioned, there is nothing to limit the current. The total charge present has nothing to do with it. Rate of change is what matters. I=dQ/dt.jasmin_123 said:Hi, Mansour_M, the question is an abstract one.
By the way, since both the discharge time and Q are limited, the current also is limited. It will not reach infinity.
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Do not be too formal! It is always worth thinking of extreme cases and singularities.
Is not it?
jasmin_123 said:Consider two identical ideal capacitors: one charged to voltage V and the other
discharged. Find steady state after connecting in parallel the charged capacitor to the
discharged one.
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Important conditions: there are NO energy losses: NO radiation, NO heat (the
connecting wires are short and superconducting), no sparks, etc.
jasmin_123 said:Hi, Learner,
Your idea is a good one. To understand what the steady state is, the following thought experiment can help.
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Let us assume that the charge of the first capacitor consists of five electrons: electrons No. 1, No. 2, No. 3, No. 4, and No. 5.
After the capacitors are interconnected, in which order the five electrons will pass to the second capacitor through ZERO resistance?
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Do you see now what the steady state is?
Learner said:In your experiment example, I don't see how it is possible to determine which electron in what order will pass to the second cap.
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