Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Register Log in

Another signals doubt....

Status
Not open for further replies.
N

Nischal

Newbie level 5
Joined
Aug 11, 2006
Messages
9
Helped
1
Reputation
2
Reaction score
1
Trophy points
1,283
Activity points
1,338
Is x[n] = cos[(pi*n^2)/8] periodic. If yes, find its period
The answer given is: Periodic. period =8
How to solve this problem?
 

Nischal said:
Is x[n] = cos[(pi*n^2)/8] periodic. If yes, find its period
The answer given is: Periodic. period =8
How to solve this problem?
Click to expand...
since ω=2Πf
assume signal is cos wn
so f=1/8

since f is expressed as the ratio of 2 inteer so it is periadic we have the condition of periodicity f=k/N
where N is fundamental period in our case it is 8.
 

Sorry for the ambiguity in the question
The question is not coswn but cos(pi*n^2/8).. here n^2 --> n squared
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top