No.mr_byte31 said:I can see the input sin signal very clear
i think the crossover distortion of the darlington is minimum as possible because of the negative feedback removes it
am I right?
The amplifier circuit is extremely simple so maybe it does not need a compensation capacitor.mr_byte31 said:thanks for the reply
then how could I calculate the capacitance?
should I but the capacitor on the transistor connected to the input signal?
I couldn't find any of those transistorspippone1987 said:Of course, but they are not so cheap. For the drivers you can use 2SC2238 and 2SA968 (respectively for pull-up an pull-down net) while for the outputs you can use 2SA1216 and 2SC2922.
I used TIP41 and TIP42 I know that it isn't logic to use them because they can't supply much current but it will be in simulation only till i find any substitutionspippone1987 said:In my opinion the distortion is minimum when you use a couple of Sziklai pair in the output stage (or CFP complementary feedback pair) which guarantee a 100% feedback
Yes, understandable. The suggestion was to increase the open loop gain, not the closed loop gain.the gain can reach 4500 but the distortion increases
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