Yes, Of course. I know its solution. It is really nice question. Don't you agree?srieda said:Do you have an answer for this??
jorgito said:AminEE,
Are you sure about the talk between P and S?
If numbers were 6 and 13, then the sum is 19 and product is 84.
But, 84 is interesting, because its factors 6 and 13 sums 19, and its factors 7 and 12 also sum 19.
(analyzing up to P=165, this case where the two diferent factorization have the same sum is unique)
Best regards!
jorgito said:AminEE,
Are you sure about the talk between P and S?
If numbers were 6 and 13, then the sum is 19 and product is 84.
But, 84 is interesting, because its factors 6 and 13 sums 19, and its factors 7 and 12 also sum 19.
(analyzing up to P=165, this case where the two diferent factorization have the same sum is unique)
Best regards!
So, they are not two prime numbers. And x*y is product of more than 2 primes.P: I can't determine the two numbers.
It means that sum x+y can not be presented as sum of two primes. So, the sum can be one of R = 11, 17, 23, 27, 29, 35, 37 ... (really they all are non prime odd numbers plus 2) Here was the idea that sum can not be even, as every even number can be presented as sum of two primes. (Goldbach has found it 300 years ago, and it is proven now for all few numbers up to 2*10^17S: I knew that.
So, it means that x*y can be presented as product of not more than 3 primes (need to be proven) and more than 2, so it has 3 prime numbers: A*B*C , and sum x+y is one of 3 variants :P: Now I can determine them.
S: So can I.
I know that.Naveed Alam said:if i m wrong.
In (1) P said:I can't determine the two numbers.
In (2) S said:I knew that.
Yes. It hasn't been asked to prove that the solution is unique, but I guess it is.why r all saying the no.s must prime...
if x=3
y=4
I'v chosen two integer number;x and y. We assume 1<x<y and x+y<100. I told x+y to Mr. S and x.y to Mr. P. I want Mr. S and Mr. P to find x and y. The following conversation done between these tow person.
P: I can't determine the two numbers.
S: I knew that.
P: Now I can determine them.
S: So can I.
FIND THE TWO NUMBERS
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