Terra_Ryzing
Newbie level 2
Hi,
I some have problems regarding the parallel RL circuit and it is the admittance magnitude. I have tried to apply the solution that was given to me in the text book. Here is my attempt on the question:
"R=2 Ohms, L=19 H & e is a 300 V, 18Hz power supply. Calculate the magnitude of the admittance of the circuit?"
The solution:
6.28x19 H x 18Hz=214.88
1/2=0.5
1/214.88=0.046
0.5^2+0.046^2 square root=502
I need someone to correct me on this. Thanks.
I some have problems regarding the parallel RL circuit and it is the admittance magnitude. I have tried to apply the solution that was given to me in the text book. Here is my attempt on the question:
"R=2 Ohms, L=19 H & e is a 300 V, 18Hz power supply. Calculate the magnitude of the admittance of the circuit?"
The solution:
6.28x19 H x 18Hz=214.88
1/2=0.5
1/214.88=0.046
0.5^2+0.046^2 square root=502
I need someone to correct me on this. Thanks.