About this MC33269 voltage regulator device.

[shemo]

**broken link removed**

on the DPAK case 368C, pin 2 is missing only pin 1 and 3. so what's pin 1 and pin 3 signals?

If I want input voltage 12V and output voltage 5V, which device type I should use?

 

[crutschow]

on the DPAK case 368C, pin 2 is mi...o draw more than about 150mA from the device.

 

[shemo]

Look at the note below the package. It states that the heatsink surface (tab) is connected to pin 2.

For 5V output you could either use the adjustable version or the devices with a part number suffix of 5.0. Note that with a 12V input you need a heat sink if you intend to draw more than about 150mA from the device.

IS this device more economic than this one https://www.amazon.com/RioRand-LM2596-Converter-1-23V-30V-1Pcs-LM2596/dp/B008BHAOQO


I want 12VDC to 5VDC 800mA output

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Look at the note below the package. It states that the heatsink surface (tab) is connected to pin 2.

For 5V output you could either use the adjustable version or the devices with a part number suffix of 5.0. Note that with a 12V input you need a heat sink if you intend to draw more than about 150mA from the device.

what's maximum input voltage for this device? it didn't specify.
if I choose MC33269DT−5.0 then this would have the DPAK, with the heatsink being the output terminal?

 

[crutschow]

IS this device more economic than this one https://www.amazon.com/RioRand-LM2596-Converter-1-23V-30V-1Pcs-LM2596/dp/B008BHAOQO

That device is a switching regulator which is more complex but has a much higher efficiency than a linear regulator such as the MC33269, thus you don't need a heatsink. But a switcher has more output noise which can be a problem in sensitive analog applications.

I want 12VDC to 5VDC 800mA output

what's maximum input voltage for this device? it didn't specify.
if I choose MC33269DT−5.0 then this would have the DPAK, with the heatsink being the output terminal?

It does specify the voltage in the MAXIMUM RATINGS chart as 20V.

The tab must be soldered to the heatsink (typically a larger area of copper on a PCB).

For 800mA output at 5V the regulator dissipation would be 5.6W which is likely more than can be readily heat sunk with that small package. Better to use a TO-220 case which can be bolted to a large heat sink. You can reduce the maximum dissipation to less the 2W if you put a 5W, 7Ω resistor in series with the input to the regulator.

For that voltage and current, why not just use the old standard LM-317. It's cheap and tough (still needs a heat-sink though).