May 31, 2006 #1 H holddreams Full Member level 6 Joined Aug 2, 2005 Messages 351 Helped 15 Reputation 30 Reaction score 7 Trophy points 1,298 Location Shanghai Activity points 4,237 How to get the (10.1) equation in the attachment? Thanks.
Jun 1, 2006 #2 V Vamsi Mocherla Advanced Member level 1 Joined Sep 6, 2004 Messages 466 Helped 72 Reputation 144 Reaction score 11 Trophy points 1,298 Activity points 5,136 Take the small signal equations for Iin, which is the input branch current and the Iout, which is the output branch current Iin = gm1* Vgs1 = gm1*Iout*R1 ---- (1) But Iout = gm2*Vgs2 = gm2*[Vdd - (R2*Iin) - (Iout*R1)] ------- (2) Replace (1) in the equation, Therefore, Iout/Vdd = 1/R1(1+gm1*R2) Please do the simple math from the above equations 1 and 2 to get the solution. I hope it helps
Take the small signal equations for Iin, which is the input branch current and the Iout, which is the output branch current Iin = gm1* Vgs1 = gm1*Iout*R1 ---- (1) But Iout = gm2*Vgs2 = gm2*[Vdd - (R2*Iin) - (Iout*R1)] ------- (2) Replace (1) in the equation, Therefore, Iout/Vdd = 1/R1(1+gm1*R2) Please do the simple math from the above equations 1 and 2 to get the solution. I hope it helps