spbhu
Member level 2
I am still not sure about this simple question:
When a 2 stage op-amp is connected in voltage follower configuration, when an input signal is applied, how will the internal node voltage of the opamp change? E.g. the drain of the input transistor? It seems it cannot be changed too much, because of the high gain, if the voltage change (e.g. by ±0.1V), then a 50v/v gain will make the output signal change by ±5V, which is not correct if Vdd is 3V.
So how do we determine the signal change at these internal nodes?
Thanks very much.
When a 2 stage op-amp is connected in voltage follower configuration, when an input signal is applied, how will the internal node voltage of the opamp change? E.g. the drain of the input transistor? It seems it cannot be changed too much, because of the high gain, if the voltage change (e.g. by ±0.1V), then a 50v/v gain will make the output signal change by ±5V, which is not correct if Vdd is 3V.
So how do we determine the signal change at these internal nodes?
Thanks very much.