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Differentiator using Operational amplifier?

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zeeshankk

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how can we desgin a Differentiator using Operational amplifier?
 

Place a cap from input to the inverting terminal of the opamp and a resistor from inverting terminal to the output terminal of the opamp. AC ground the non inverting terminal of the opamp. This will act like a differentiator.
 

Zeeshankk,
Aryajur is correct. However there are some caveats regarding differentiators. Recall that the the closed loop gain of the inverting cofiguration is Zf/Zi, where Zf is the feedback impedance, Zi is the input impedance. At high frequencies the input impedance, which is the input capacitive reactance, is very low. The result is that the gain is very high at high frequencies, resulting in high noise sensitivity. You can minimize this effect by placing a resistor (Ri) in series with the capcitance Ci, producing a non-ideal differentiator. The corner frequency, in Hz, thus created is equal to 1/(2pi*Ri*Ci). You can create a 2nd low pass corner by placing a capacitance Cf in parallel with the feedback resistor Rf. This low pass corner frequency will be equal to 1/(2pi*Rf*Cf) .
Regards,
Kral
 

what aryajur saying is ideal and what kral syaing is practical differenatitor.i would like to endorse the view expressed by kral that ideal diff. will have worst performance in noise presence so we are traversing to idea of using a practical diff.
 

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