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* To find out sign of result: XOR both input sign bits
* then make both inputs positive ( ==> only 3 bits unsigned)
* multiply both values: 3 bits x 3 bits = 6 bits result
* If the result is negative (output of XOR) then invert the multiplication result
* form a 7 bit signed integer
Just the 3 x 3multiplication:
Let's say ABC are the three bits of the first multiplicator
And XYZ of the second multiplicator:
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