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BTW: this equotation is contrary and has not solutions ! Substitute 1 for a variable and check it yourself.
See: 1^7-2*1^5-1^2 = -1
1-2-1 =-1
-2=-1 -> equotqtions is contrary and has no solutions![/QUOTE
Sorry- English is not my mother tounge. It shouyld be: contradictory equotation
There is no point to solving these eqotation because it is contradictory, and has no solution.
Maybe you made mistake during writing this equotation if yes please give proper form of this eqotqtion.
Regards
this equotation is contrary and has not solutions ! Substitute 1 for a variable and check it yourself.
As shown by wwfeldmann, the post #1 equation has real roots. Similarly the equation in post #5 has two real roots, x=3.987 isn't among it, but x≈-1.2 and x≈1.3.
Post #1 suggests that you want to synthesize hardware logic to perform the calculation. But this is neither useful nor simple.
Firstly it's not useful because the solution is constant and can be calculated at compile time. You can however define a different problem involving variable coefficients as input. Then there's something to calculate at run time.
Secondly it's not simple because real variables aren't synthesisable in logic hardware. You can use either fixed or floating point variables for the calculation.
BTW: this equotation is contrary and has not solutions ! Substitute 1 for a variable and check it yourself.
See: 1^7-2*1^5-1^2 = -1
1-2-1 =-1
-2=-1 -> equotqtions is contrary and has no solutions![/QUOTE
Sorry- English is not my mother tounge. It shouyld be: contradictory equotation
There is no point to solving these eqotation because it is contradictory, and has no solution.
Maybe you made mistake during writing this equotation if yes please give proper form of this eqotqtion.
Regards
Sorry,
I did a mistake, some kind of brain fade :lol:
regards