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yoyobaby,
This depends on the communication system. A commonly used system is one in which a frame consists of 1 start bit, 1 stop bit and 8 data bits. In this example, you would not have enought data bits. You would have to multiply the baud rate by 10/8 = 1.25. If you could supply more details about your system, I could probably come up with a better answer.
Regards,
Kral
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