Cecemel
Member level 5
Hi,
The title pretty much says it all. I’m not sure what factors these losses are based on. I saw somewhere you need to multiply the sum of the rise and fall time by the drain-source voltage and current, but I don’t think the losses are this high.
Thanks
The title pretty much says it all. I’m not sure what factors these losses are based on. I saw somewhere you need to multiply the sum of the rise and fall time by the drain-source voltage and current, but I don’t think the losses are this high.
Thanks