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It seems to me you may know how it works but don't know what the circuit looks like. i.e. the boolean equation.I know how 2:1 mux work, but i missed one lesson. I don't know how convert an circuit into mux
does the problem expect you to use a 2:1 mux as an inverter?
does the problem expect an optimal solution? eg, one that allows a/b/c to be mux inputs?
First, a 2:1 mux can create an inverter, an and-gate, and an or-gate. Even without effort, you could construct the mux circuit based on replacing and/or/invert with the mux2 version. You can prove this to yourself by applying 1/0 to one of the mux inputs, a0 to the other input, and a1 to the select. There are four possible cases, so you can quickly determine which one is whcih. I'm using a0/a1 as the variable name has nothing to do with a/b/c from the problem. Just that you can get a0 and a1, a0 or a1, as well as !a0.
This problem probably doesn't want you to do this. It probably wants you to notice that there are only two cases where there is a 1 output. from there that both expressions use the same inputs, but with opposing polarity. This should suggest choosing one input as a select. Then use the above and/or conversion for both mux input cases.
Hi,
Never leave an unused input floating.
Klaus
It is the second one, At the end is the same exercise. I want understand the logic to solve this kind of problem.