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[MOVED] Boolean implementation using multiplexer

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sunidrak

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hi,

how to implement this using mux??

f(A,B,C)=A+(Abar)B using 4:1 Mux

i knw how to implement F(A,B,C)=Σ(0,1,5,6) using 4:1 Mux
my question is how to bring the reduced form of boolean expression to its original form , so to implement it using Mux??
 

Re: Boolean implementation using multiplexer

Seems simple to just spell-out the four function possibilities like this ...
A | B | Y | MUX-input
--|---|---|------------
0 | 0 | 0 | In0
0 | 1 | 1 | In1
1 | 0 | 1 | In2
1 | 1 | 1 | In3
The Y column is the tied-off level at the four corresponding MUX inputs.
And then A feeds into Select1 and B feeds into Select0 of the MUX.
But this seems too obvious and I must be misunderstanding the real question?
 

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