plz help me to solve this in matlab imp

dear all
i want to simulate prog in matlab for ofdm papr reduction
statement: i have matrix of 941*1 i wan 2max values from 1st 62 elements then anoter 2 frm next 62 so on..

plz help me its much imp for me

Hey, Here is the matlab code, I took the matrix of 15 *1 and tried to find the max values for 1st 6 elements. Just change those parameters in the code:

clc
clear all;
a = [ 1; 5; 6; 3; 6; 9; 8; 4; 5; 8; 0; 0; 0; 0; 1]; % Your vector=941x1
x = length (a);
n = 6; % Need to find the max from 1st numbers, In your case 62

iter = ceil(x/n);

for i=1:iter
max(i) = 0;
if (i==1)
for j = 1: n*i
if (a(j)>max(i))
max(i) = a(j);
end
end

else
for j=n*(i-1)+1:min(n*i,x)
if (a(j)>max(i))
max(i) = a(j);
end
end

end

end


Enjoy.
-sv

vibhutesachin said:

dear all
i want to simulate prog in matlab for ofdm papr reduction
statement: i have matrix of 941*1 i wan 2max values from 1st 62 elements then anoter 2 frm next 62 so on..

plz help me its much imp for me

Click to expand...

I did not understand you very much but what i understood is the following:
%% Function to divide the input sequence to sub sequences
% s2mss - Function
% 1. (s) Input the data
% 2. (hl) Length of the subsequence
% 3. Outpot of the function is an array st(m,v).
% Montadar Abas Taher
% 12/03/2011
function [m outs]=s2mss(cd,hl)
L=length(cd);
Na=0.75*hl;
n=log(hl)/log(2);
Nu=L/(3*2^(n-2));
count=ceil(Nu)-1;
k=[];
s=[];
if L<Na
k=cd;
end
if L>Na
%disp('L > Na is OK here in line 21 of s2mss.m')
for b=0:count

if b==count
[a1 b]=size(k);
a=a1*b;
cdL=length(cd);
subt=cdL-a;
s=cd(end-subt+1:end);
factor=b;
end

try
k(b+1,=cd(b*Na+1:Na*(b+1));
end




end
end
sl=length(s);
nsl=b;
ns=[s zeros(1,nsl-sl)];
lns=length(ns);
st=[k;ns];
outs=st;
[m1 v]=size(st);
m=m1;

jakyshan1990 (Re: plz help me to solve this in matlab imp

are 2max values that you want should be equal??????????????)


what do you mean?

i mean the two max values he want from every 62 elements ...carry same vaule or ==>frist max value then secoun max smaller than first