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nead an out put of simple logic circuit

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sagar474

sagar474

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what will be the out put Y of the circuit
Those are nand and nor gates...
 

Y = ( ( (A nand B) nand B ) nand B) nor ( ( (A nand B) nand B ) nor C)

Simple really.
 

    sagar474

    sagar474

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I'am sorry, if you work in electronic field, you must be able to read this kind of simple logic, don't borrow every body with so stupid question.
 

but what is the result? i got AB is it correct? but i cant find it in the choice.
 

rca said:
I'am sorry, if you work in electronic field, you must be able to read this kind of simple logic, don't borrow every body with so stupid question.
Click to expand...

I apologize for below words rca.

If you dont want to aswer then no one has force you, but please dont insult others.

One more thing how stupid question is depends how much you knows? If some one has feeling of learning and if he has not idea to that then let him try.

Please forgive me if this words hearts you, but dont forget that every one has not equal level of knowledge and even though every one is trying.


sagar474 said:
but what is the result? i got AB is it correct? but i cant find it in the choice.
Click to expand...

I got AB + C, i tried once only if i had not do any mistake then this is correct answer.

Let me try to explain you need to follow gates from left to right.
say first gate output is X1 = AB , simple AND gate;
2nd gate output is X2 = X1xB = ABxB = AB;
3rd gate output is X3 = X2xB = ABxB = AB;
4th gare output is X4 = C + X3 = AB + C;
and final output Y = X3 + X4 = AB + AB +C = AB + C;

Try to read boolean algebra for boolean operation that might help you.

HTH,
Regards,
Shitansh Vaghela
 

    sagar474

    sagar474

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thank you for your response shitansh. but the choices are like this.
 

From first figure It seems that there are AND and OR gate but in 2nd figure I can see that gate used are NAND and NOR, if that is case then similarly you need to derive output.

Write your effort here and if there is any thing wrong you did probably some one will pointed out you.

Regards,
Shitansh Vaghela
 

    sagar474

    sagar474

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Stick it through a synthsisor - it will minimise the equation for you.
 

Sounds like you have not heard of **broken link removed**. It's an online simulator where you can build this circuit very quickly and see how it works.
 

    sagar474

    sagar474

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sagar474 said:
thank you for your response shitansh. but the choices are like this.
Click to expand...

None of those choices matches the circuit behavior. Since you've shown your work, I would say that from a static perspective I agree with it. The circuit appears to compute A*B, without regard for C, when the inputs are steady. If A is high and B goes from low to high, the output edge may not switch cleanly; depending upon the relative propagation delays of NAND and NOR gates, the behavior may or may not be affected by C.
 

thank you guys. I concluded the answers given in this book is wrong.
the answer is AB
 

My answer is (d) C. I have to double check it first. Since rca knows so much, maybe he can "borrow" us with his answer.
 

The result i find is (A and B)
this is the expression as TrickyDicky said
Y = ( ( (A nand B) nand B ) nand B) nor ( ( (A nand B) nand B ) nor C)

A=0,B=0 ( (A nand B) nand B ) nand B)=1 this goes to a nor so result always 0, the second part doesn't matter
A=0,B=1 ( (A nand B) nand B ) nand B)=1 this goes to a nor so result always 0, the second part doesn't matter
A=1,B=0 ( (A nand B) nand B ) nand B)=1 this goes to a nor so result always 0, the second part doesn't matter

A=1,B=1 ( (A nand B) nand B ) nand B)=0
in this case the second part ( (A nand B) nand B )=1, this goes to a nor with c but the result will always be 0
so finally (0 nor 0) =1

so c is irrelevant and the output is actually (A and B)

Alex
 
Last edited:

I got the answer A.B.

I have assumed that the logic gates are NAND and NOR.
 

I agree. I rushed my first attempt, but I get the same answer now.
 

sagar474 said:


what will be the out put Y of the circuit
Those are nand and nor gates...
Click to expand...

i think always result will be zero, what u say

---------- Post added at 06:43 ---------- Previous post was at 06:27 ----------

it will A and B
 

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