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CRLH Transmissionline

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gemmy94

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I am designing a CRLH TL in microstrip line. From the equivalent circuit of CRLH TL, in theory, the left-Inductance can be get by connect the conductor on the upper plane of substrate to the ground plane(bottom face). From what i learn, it can be done by 2 ways:
- use the via (conventional)
- use the Strip line
My question is how to create left-Inductor by using strip line, i cant understand what to do to connect the upper face to the bottom without a via.
I have read a paper about a virtual ground that is on the upper plane. Is that an idea for this problem? Someone know about this (create left-Inductor), please help me!
Thank you so much!!
 

Hi gemmy94,

What do you mean by "strip line"? Usually the only metallization between layers of a substrate is in the form of a via.
 
I presume "left inductor" is referring to "LL" (the shunt inductor) in the usual CRLH (composite right/left handed transmission line) scheme.

For a good reason, Edaboard rules say it's not allowed to use "Technical abbreviations unless they are universally understood, they will confuse members and make it hard for them to understand what you mean."

I believe the OP didn't consider this point.
 

gemmy94 said:
So, the only way to create Left-Inductor is to use the via. I have read one paper about use the via-less
https://ieeexplore.ieee.org/xpl/freeabs_all.jsp?arnumber=6408784&abstractAccess=no&userType=inst
I mean, is it possible to creat L-left without a via. It would be easier in implement.
Thank you for your care
Click to expand...

See, the left-handed inductance is actually given by the meander line (fig. 2(a) of the paper). The idea here is that that stub after meander line is so large that it acts as a short to ground (the capacitance between stub and ground is so high that at operating frequency it act as a SC). The effect is the same as putting SC vias, but some applications don’t allow it and this design is an alternative.
 
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