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Binary number conversion

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varunme

varunme

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How can we take the number of "high"s in a binary number ?

like

0b10100000 -> 2
0b01000101 -> 3
0b01111000 -> 4
 

You need to check every bit, then if bit high, increment counter.
Code: 
j=0;
for(i=0 ; i < 8 ; i ++)
     if(((DATA>>i)&1) == 1) j++;
 
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    varunme

    varunme

    Points: 2
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srhoar,
Very nice links, I didnt got any links like this before
 

engshahrul said:
You need to check every bit, then if bit high, increment counter.
Code: 
j=0;
for(i=0 ; i < 8 ; i ++)
     if(((DATA>>i)&1) == 1) j++;
Click to expand...

what can be the problem with the bel

Code: 
void main()
{
         port_B =portb;
         DATA = port_B;
        while (1) {
         if (UART1_Data_Ready()) {
        j=0;
      for(i=0 ; i < 8 ; i ++)
      {
       if(((DATA>>i)&1) == 1) j++;


       }
        m=Int2Str(j);
       UART1_Write(m);



    }

     }

}



used

Code: 
        UART1_Write(Lo(J));
       UART1_Write(Hi(J));

too, but no luck
 
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