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I did this, but apparently each each of those instructions disassembles to one assembler instruction. This means that I should get, at least for logical '0' approximate 1usec time (with 1MHz system clock).
But I still get 10usec. There is some factor of 10 in instruction execution...
Hi ,
I use eval board "LaunchPad" I set CLK to 1MHz.
When I try to check the maximum on-off rate on one of the pins I get 10usec - 100KHz.
Doing just:
while(1)
{
P1OUT = 0;
P1OUT = 0xff;
}
The problem is that system clock is 1MHz, but this code gives my only 100kHz.
What can be a problem...
Hi,
I have very primitive question.
I cannot find what is the maximum sample rate for MSP430F2003
**broken link removed**
This is microcontroller from TI.
Please , help me with this.
Thank you.
Actually it will depend on your application. For example bias currents: if Ib=10uA so you cannot put 1M resistors. Also input capacitance, it will form LPF with resistor and slow down signal. Noise. Current feedback Opamps have specific resistance in order of hundreds of ohms that you can put in...
There is a link to Analog Lecture notes sites **broken link removed** (it was posted several days ago), you can find it there. Also you can use datasheet of REF200 part.
It might be because of the input capacitance of the OpAmp, but oscillation frequency is to low for this. It also can be because of the OA self transfer function.
Try to put a resistor in series to the OA output (before feedback closure).
The transient in the waveform is around BW cutoff of the circuit. Can you elaborate more, what exactly are you showing? Is is written there "N differential..?"
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