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i have a generic input signal say a(generic-1 down to 0). and i have generic input values, say i(generic-1 down to 0).
what i need is
output = a(0) and i(0)+ not a(0) and a(1) and i(1)+ not a(0) and not a(1) and a(2) and i(2) + and so on up to generic-1.
i got this question in a quiz
i am attaching the exact image.
the fourth option missing is "both are equally fast".
what i thought fast means "output is raising quickly". i still have the confusion whether fast means this or "how quickly it reaches steady state"
for the second image i attached,
i assumed 50% feedback only.
it means gain of non inverting =2 and that of inverting is 1(phase is 180 deg)
as u said same feedback factor for both circuits.
i took the closed loop response of both configurations as (1/(s+1)) and (2/(s+1))
i found the output...
i deduced the transfer function for both the configurations with single pole. what i observed is, the non inverting configuration has higher gain compared to inverting configuration and the pole locations are same in the closed loop.
the problem is now simpler,
we have two frequency responses...
but sir,
if we take from the perspective of time response, t=0+ represents the transient response , and the 1.294 v is the steady state value. so if v(t=0+ )=1.294 V instead of 0.8 V, it has bypassed transient and reached steady state?
i am really confused.
thanks for ur suggestion
i solved the other way as u said, here it is
but the question that arose is
why and how energy is dissipated for charge sharing?
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