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But your test setup is far from "unregulated DC". Instead it´s the opposite. It´s pure AC, no DC at all.unregulated DC...
There is only one capacitor and it already has a value: 10uF. What do you want to calculate?how to calculate the capacitor value?
You ask us? We don´t know what your idea is, thus it´s rather on us to ask about what you want to achieve.1. this part of the circuit comes after the transformer, diode ring and capacitor?
It means DC , but the voltage level is not stable.2.unregulated dc means fluctuating dc signal?
i am just learning things here, i found this circuit diagram and wanted to know what it does. that is i don't have any aim to build it for anything/projects like that just to know what is it. the capacitor value i just used randomly without knowing how to actually calculate it.Hi,
But your test setup is far from "unregulated DC". Instead it´s the opposite. It´s pure AC, no DC at all.
If you want DC input, then also test it with DC input.
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There is only one capacitor and it already has a value: 10uF. What do you want to calculate?
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You ask us? We don´t know what your idea is, thus it´s rather on us to ask about what you want to achieve.
It means DC , but the voltage level is not stable.
Klaus
correct me if i wrong but the 1N5242B has max zener voltage of 12.6VPretty much everything here is wrong.
Maybe if you applied a DC voltage instead of an AC voltage your circuit would work. It's a good thing you didn't actually build this circuit because chances are it would burst into flames.
You're applying 120V to a transistor that has a maximum voltage of 40V.
You're dissipating 10W across that 1K resistor.
It's a voltage regulator, not a rectifier.
i know from replies that the input signal was wrong, but i am asking whether the diode maximum voltage is 12.6V or notAre you expecting that the zener diode reduces the transistor voltage? It doesn't, the transistor has to be still rated for the maximal input voltage. Also power dissipation of all components must be observed.
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A strange detail of the post #1 circuit hasn't been addressed yet. How does it achieve -110V output across two forward biased diode junctions (transistor CB junction and Z-diode)? The simulated input current is probably several 100A.
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The simulator can measure it without burning your face.
do you know how to do an internet search?i know from replies that the input signal was wrong, but i am asking whether the diode maximum voltage is 12.6V or not
TUN??Also, 2N3904 is a TUN, if Vbe max. is 6V, why the 12V Zener rather than a 5.6V Zener? Vcb is max. 60V, as well. Absolute maximum ratings and recommended operating conditions. Datasheets are very helpful. Normal is: idea > schematic > datasheets > simulation and/or prototype > final version of circuit. Once the headache of gradually understanding their hieroglyphics and strange terminology is gone, datasheets are as important as the component.
Hi Barry,TUN??
The 12V zener because the intended output voltage is 12V, not 5.6V. (-Vbe, approximately 0.6V).