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Hi,
I need to calculate current (Ic) in the attached embedded circuit diagram. I'm new to circuit theory. Can anyone please calculate and let me know. Thanks in advance
KB844A is an opto-isolator. The Ic current is the output coming from the npn transistor which need to be controlled in the circuit design. It has to be within 5mA to 20mA (looking into the datasheet).
You probably didn't understand the answer by ravindragudi. The current is defined by the connected load resistance. It's not shown in the schematic, you can't calculate Ic.
The possible range is however restricted by the opto coupler current transfer ratio and the LED current If. Usually the connected circuit is designed so, that the minimal expectable Ic value is sufficient to drive it, e.g. make Rload > 5V/(If *ctr)
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