JackofallTrades
Newbie level 6
I didn't see where else to post this so feel free to move it to the proper section if there is one.
I have a pull type solenoid very similar to what is shown here.
**broken link removed**
Yesterday, it stopped actuating. After testing the drive circuit, I checked the solenoid itself.
Originally, this solenoid had a coil resistance of 4 ohms.
Now, not working, it has a coil resistance of 10 ohms. I'd like a theory on how this came to be.
If the wire had burnt through, I would expect an open circuit. If the insulation had failed/melted and coil winding where touching, I would expect a lower resistance. The only theory I have is that this solenoid must use multiple windings in parallel. One or more of these burnt through, leaving only less parallel coils and thus a higher resistance?
Thoughts?
(The windings are sealed in a metal case and I cannot easily inspect them.)
I have a pull type solenoid very similar to what is shown here.
**broken link removed**
Yesterday, it stopped actuating. After testing the drive circuit, I checked the solenoid itself.
Originally, this solenoid had a coil resistance of 4 ohms.
Now, not working, it has a coil resistance of 10 ohms. I'd like a theory on how this came to be.
If the wire had burnt through, I would expect an open circuit. If the insulation had failed/melted and coil winding where touching, I would expect a lower resistance. The only theory I have is that this solenoid must use multiple windings in parallel. One or more of these burnt through, leaving only less parallel coils and thus a higher resistance?
Thoughts?
(The windings are sealed in a metal case and I cannot easily inspect them.)