Relationship between SR and GBWP

[Nugget]

gbwp closed loop

One say : the more GBW , the faster op amp ? What means speed of op amp ?
What is the relationship between SR and GBW ? could anyone let me know clearly ?
Thanks a lot

 

[flatulent]

Gain x Bandwidth is a small signal parameter. Slew rate is a large signal parameter. Both of them are controlled by capacitances, but the slew rate is affected by bias currents. So, they are only slightly correlated.

 

[MLR67]

Hello
on my point of view ou have a correlation between SR and BW.
I give you an example:
if your are desingning an OTA the bandwith is gm/CL and gm=I/(Vgs-VT)
The output slew rate (external slew rate) is given by SR=dvmax/dt=k.I/CL where k is a multiplicative factor (k≥1 )
So you have a correlation between SR and BW (closed loop)

 

[maharshi_qis]

current decides the ckt gain which inturn decides the UGB of the opamp.
similarly current also decides the Slew rate of the op-amp.
see analog design itself multi dimensional optimization.
we cant say no parameter depends on other..

 

[satyasiva]

SR is a large signal parameter ok, but GBW product tells us info. abt how our circuit can operate at high frequencies. Thus if we have a good GBW product, i think we can have a good SR.

 

[dodoro]

i highly recommand you to see David Johns and Ken Martin's book. it was thorouly explained in the book.

 

[HenNavarre]

the faster the circuit, high transition frequency, the higher the slew rate so it seems they correlate