Rayleigh or Ricean fading??

[moonnightingale]

i m pasting the question and solution as well . kindly tell me how it is rayleigh

 

[ColonelTigh]

Your answer is right there. Rician has a dominant line-of-sight path plus smaller scattering paths. Rayleigh does not.

 

[moonnightingale]

but how can we know that its power is uniformly distrubuted.
What is the clue in the equation

 

[ColonelTigh]

From here, Rician Fading, the channel response to a sinusoid input is h(t) = C*Dirac(t - t0) + sum(rho_n * Dirac(t - tn)). For a Rician channel, C is non-zero and larger than the rho_n components. This is your direct LOS path with time delay t0. The autocorrelation of h(t) is your Ac(t,del_t) from the problem. If C is non-zero, you get a component with fixed delay in your autocorrelation function.

Hope that helps!