Nab
Member level 4
- Joined
- Mar 28, 2007
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hello,
plz it's a small problem , but i need it , it's very important for me and very urgent [45point or more as you like]
i have to give the proof of this
for p≠0, 2π, 4π, ... and q≠0, 2π, 4π, ...
y(p,q) = (1/N) Σ exp ^{i(pl+ql²)} = 0 when N goes to infinity ( l goes from 0 to N-1)
In latex
y(p,q)=\frac{1}{N} \sum^{N-1}_{l=0} e^{i(pl+ql^{2})}=0 when N goes to infinity
if you can not plz just this
for q≠0, 2π, 4π, ...
y(q) = (1/N) Σ exp ^{iq²)} = 0 when N goes to infinity ( l goes from 0 to N-1)
in latex
y(q)=\frac{1}{N} \sum^{N-1}_{l=0} e^{i(ql^{2})}=0 when N goes to infinity
here is my email nabkorso (at) gmail (dot) com
THANK YOU THANK YOU THANK YOU
plz it's a small problem , but i need it , it's very important for me and very urgent [45point or more as you like]
i have to give the proof of this
for p≠0, 2π, 4π, ... and q≠0, 2π, 4π, ...
y(p,q) = (1/N) Σ exp ^{i(pl+ql²)} = 0 when N goes to infinity ( l goes from 0 to N-1)
In latex
y(p,q)=\frac{1}{N} \sum^{N-1}_{l=0} e^{i(pl+ql^{2})}=0 when N goes to infinity
if you can not plz just this
for q≠0, 2π, 4π, ...
y(q) = (1/N) Σ exp ^{iq²)} = 0 when N goes to infinity ( l goes from 0 to N-1)
in latex
y(q)=\frac{1}{N} \sum^{N-1}_{l=0} e^{i(ql^{2})}=0 when N goes to infinity
here is my email nabkorso (at) gmail (dot) com
THANK YOU THANK YOU THANK YOU
