I have seen the answer for when to consider PCB trace as a transmission line in many places. The answer is "Typically, if the signal pulse rise time is ‘small’ compared to the time it takes for the signal pulse to propagate (e.g. ½ of the total time the signal takes to travel along the trace) then you need to consider your PCB as a high-speed circuit".
But no one explains how the SI problems arise when the rise time is smaller than 2XPropagation delay.
May I know
1) what happens to a signal when it's RISE time is less than the propagation delay.
2) How this condition will make SI issues to come.
But no one explains how the SI problems arise when the rise time is smaller than 2XPropagation delay.
May I know
1) what happens to a signal when it's RISE time is less than the propagation delay.
2) How this condition will make SI issues to come.