AdityaRajNayak
Junior Member level 1
I have a 12V 2Amp DC Adapter. I have designed a power supply circuit using 7805(without heat sink). I want to give the output of the adapter as the input to this power supply circut. But as per my study 7805 shuts down in case current goes beyond >600 mA, and so the output at 7805 is not 5V(Please correct if my understanding is incorrect). Request to suggest some circuit I could use inbetween the Adapter and Power Supply circuit so that I can reduce the current upto atleast 1A~.5A so that it becomes useful for 7805.
Below is the block diagram:
<12V/2A DC Adapter > --------- <?? Circuit ??> ----------< Power Supply circuit with 7805 IC that can tolerate max .5A without Heat Sink>
[Query] Need help on <?? Circuit ??> in the above diagram.
Below is the block diagram:
<12V/2A DC Adapter > --------- <?? Circuit ??> ----------< Power Supply circuit with 7805 IC that can tolerate max .5A without Heat Sink>
[Query] Need help on <?? Circuit ??> in the above diagram.