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So the end result will be 6V DC 0.6ampsMAX?
The voltage on the 910 Ohm will be 6v-1.2v = 4.8v
4.8v * 4.8v / 910 Ohm = 0.025W
..explain to me what happened..
I connect a small light bulb to 6V 0.6A and everything was fine, but when I connected it to 6V 1.5A light bulb burned instantly.
It is normal for an old incandescent light bulb to burn out the moment it is turned on because the sudden jolt of power breaks the brittle filament. If the power was applied slowly then the light bulb might still work.
A light bulb powered from the mains or another very powerful power source burns out the moment it is turned on because when it is cold, its filament is a much lower resistance than when it is 2000 degrees C so the current is 10 times normal and it blows the filament. If the supply is AC and the bulb is turned on the moment the AC voltage is at a peak then the instantaneous power in the bulb is double its normal continuous power times 10 because it is cold.